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nekit [7.7K]
3 years ago
14

Mia has $40 in a savings account. She will start adding $5 to her account each week. Juan has $15 in a savings account. He will

start adding $10 to his account each week. Write a system of two linear equations to represent the situation.
Graph the system of equations you wrote in Part A.
Mathematics
1 answer:
____ [38]3 years ago
4 0

Answer:1

Step-by-step explanation:

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Megan has 40$ in her wallet. She wants to buy a dress. The regular price of the dress is 45$. The dress is sold at a discount of
devlian [24]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
Select all the functions whose graphs include the point (3, 12)
anygoal [31]

1.   Y=4

2.  Y=2

3.  Y=X

4.  Y=2

(X,Y)

i hope this helps

Step-by-step explanation:

8 0
3 years ago
Sue's Sushi placed two orders with its fish supplier. One order was for 11 pounds of salmon and 6 pounds of tuna; the order tota
lidiya [134]
Hi there

One pound of salmon will cost $13, and one pound of tuna will cost $8.

Here's why.

X will be the cost of pound of salmon, and y will be the cost of a pound of tuna.
| 15x+8y=259
| 12x+6y-204

6y = 204-12x
y=34-2x

15x+8(34-2x)=259
272-259=16x-15x
x=13

y=34-2*13
y=34-26
y=8

So, again...
1lb Salmon : $13
1lb Tuna : $8
3 0
3 years ago
Solve the following word problem. A man travels from town X to town Y at an average rate of 60 mph and returns at an average spe
sladkih [1.3K]

Answer:

  • d = 1650 miles

Step-by-step explanation:

Let the distance be d

<u>Then the time in travel is</u>

  • d/60 one way, d/50 on return

<u>The round trip would take 1/2 hours longer if the average speed was 55 mph</u>

  • d/60 + d/50 = 2d/55 + 1/2
  • d/60 + d/50 - 2d/55 = 1/2

LCM(60,50,55) = 11*12*5*5 = 3300

  • 55d/3300 + 66d/3300 - 120d/3300 = 1/2
  • d/3300= 1/2
  • d = 1650 miles

4 0
3 years ago
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