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givi [52]
3 years ago
14

What is the equation of the perpendicular line 2x-4y=7 passing through the points (2,-5/4)?

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

y= 2x-5\frac{1}{4}

Step-by-step explanation:

We are given;

The equation 2x + 4y = 7

A point (2, -5/4)

We are supposed to determine the equation of a line perpendicular to the given line;

First, we determine the slope of the given line by writing the equation in the form of y= mx + c

2x + 4y = 7

y = -1/2x + 7/4

m₁ = -1/2

But, for perpendicular; m₁×m₂= -1

Therefore;

-1/2 × m₂ = -1

m₂ = 2

Thus, we can get the equation of the line;

Taking another point (x, y)

\frac{y+\frac{5}{4} }{x-2}=2

y+\frac{5}{4}= 2(x-2)

y+\frac{5}{4}= 2x-4

y= 2x-4-\frac{5}{4}

y= 2x-5\frac{1}{4}

Thus, the equation of the line in question is y= 2x-5\frac{1}{4}

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Therefore:

3/4 − (-5/12) = 1 \frac{1}{6}

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