Answer:
Step-by-step explanation:
The key here is knowing that the equation of the line that passes through these points is same
Thus having (6,14) and (0,0), the slope is as follows;
m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3
Now we can use this slope here to get the value of y in the question
All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)
That would be;
7/3 = y-14/1-6
7/3 = y-14/-5
cross multiply;
-35 = 3(y-14)
-35 = -3y + 42
-3y = -35-42
-3y= -77
y = -77/3
y = 77/3
I would substitute y = x^2
4y^2 -21y+20=0
A(n,s)=(ns^2)/(4tan(180/n)), n=number of sides, s=side length
A(8,4.6)=(8*4.6^2)/(4tan22.5)
A(8,4.6)=42.32/tan22.5 m (exact)
A(8, 4.6)≈102.17 m^2 (to nearest hundredth of a square meter)
First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them
12x^8/3x^3= 4x^8-3=4x^5
20^2x=20^x*20^x
m^5*m^-7=m^5-7=m^-2
