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Aliun [14]
3 years ago
12

Compare the quantity in Column A with the quantity in Column B.

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

It Is My Work From My Laptop

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Each of the 9 parking lots at an automobile plant holds the same number of new cars. The lots lots are full. If there are 431 ca
Serjik [45]

431 \div 9
=47.8888 when you round it up you can get get about 48 then you estimate to about 50.
3 0
3 years ago
1/2 + (-1/4)=????????????
erica [24]

Answer:

\frac{1}{4}

Step-by-step explanation:

\frac{1}{2} = \frac{2}{4}  We need a common denominator before we can add.

\frac{2}{4} + \frac{-1}{4}  means the same thing as

\frac{2}{4} - \frac{1}{4} = \frac{1}{4}

5 0
1 year ago
What is 9540000 in expanded form using exponents to show powers of 10
GalinKa [24]
<span>9540000 = 9x1000000 + 5x100000 + 4x10000
               = 9x10^6  + 5x10^5 + 4x10^4</span>
3 0
3 years ago
Read 2 more answers
A projectile is shot into the air following the path,h(x) = - 5t2 + 20t + 3. At what time will it reach a maximum height? t = 1
kramer

Answer:

t = 2

Step-by-step explanation:

Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.

Recall that the formula for the position of the vertex in a general parabolic function of the form: y(x)=ax^2+bx+c, is given by the expression: x_{vertex}=-\frac{b}{2a}

In our case, the variable "x" is in fact "t", the leading coefficient (a) is -5, and the coefficient for the linear term (b) is 20.

Therefore, the maximum of the path will be when t=-\frac{20}{2(-5)} =\frac{20}{10} =2

7 0
3 years ago
Remember to check for extraneous solutions
larisa86 [58]

Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}

3 0
3 years ago
Read 2 more answers
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