2/6 = 1/3 = 20 minutes
1/2 = 30 minutes
20 + 30 = 50 minutes
50 minutes x 7 = 350 minutes = 5 hours and 50 minutes
5 x $5.25 = $26.25
50 minutes = 5/6
5/6 of $5.25 = 4.375
Add $26.25 to the total for 50 minutes to get your answer. :)
<h2>
Step-by-step explanation:</h2>
Interest, is an additional money paid for borrowing money. it could be simple or compound interest.
simple interest= p×T×R/100
when interest is compounded annually
F= p(1+r)^t
F= future value
p= principal
r= rate
t= time
compound interest is calculated based on the initial and accumulated interest.
<h2>interest Linda earns</h2><h3>fist year</h3>
F= p(n+r)^n
F= 10000(1+0.02)^1
F= 10000×1.02= $10200
interest= 10200-10000
interest = $200
second year
F = 10200(1+0.02)^1
F=10200×1.02= $10404
Interest= 10404-10200
interest= $204
third year
F= 10404(1+0.02)^1
F= 10404(1.02)
F = $10612.08
interest= 10612.08-10404
interest= $208.08
<h2>Bob's interest</h2><h2>I= p×t×R/100</h2>
first year
I=10000×1×0.02/100
interest= $2
second year
I= 10000×2×0.02/100
interest= $4
for the third year
I =10000×3 × 0.02/100
interest= $6
<h2>check answer above for final computation</h2>
Answer:
From least to greatest: -2, 2/3
Step-by-step explanation:
Set each factor equal to 0 and solve
2x + 4 =0
2x = -4
x = -2
3x - 2 = 0
3x = 2
x = 2/3
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5