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Tju [1.3M]
3 years ago
8

Which is the area of this triangle?

Mathematics
2 answers:
sattari [20]3 years ago
7 0
Formula : bh/2 so it's 2(4)/2= 4
Svetllana [295]3 years ago
4 0

Answer:

It should be 4

Step-by-step explanation:


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Help me find measure of angle 1!
yulyashka [42]

Answer:

its 90

its a right angle triangle

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What does it mean when a line of best fit has a correlation coefficient close to 0?
stepladder [879]
That the relationship is nonlinear
5 0
4 years ago
The line with equation a + 4b = 0 coincides with the terminal side of an angle θ in standard position and cos θ > 0. What is
ankoles [38]

Answer:

Option A. -(\frac{\sqrt{17}}{17})

Step-by-step explanation:

Equation of a given line is a + 4b = 0 or b = -\frac{1}{4}a

This in the form of y = mx + b, which is slope-intercept form.

Here slope of the line is (-\frac{1}{4}).

Or tanθ = \frac{(-1)}{4}

This line coincides with the terminal side of the angle in standard position where cosθ > 0

Since tanθ = \frac{\text{Height}}{\text{Base}}

and sinθ = \frac{\text{height}}{\txt{Hypotenuse}}

Hypotenuse = \sqrt{\text{height}^{2}+\text{Base}^{2}}

                     = \sqrt{(1^{2}+4^{2})}

                     = \sqrt{17}

Since tanθ is negative and cosθ > 0 that means θ lie in fourth quadrant.

Therefore, sinθ will be negative.

[ \frac{-sin\theta}{+cos\theta}=-tan\theta ]

sinθ = -\frac{1}{\sqrt{17}}

       = -\frac{1}{\sqrt{17}}\times \frac{\sqrt{17} }{\sqrt{17}} = -\frac{\sqrt{17}}{17}

Answer will be option A.

6 0
4 years ago
26. Tony collected $1072.61 from 49 customers
pashok25 [27]
$1072.61/49 = $21.89
Each person gave him $21.89
6 0
3 years ago
What is the height of a cylinder with a volume of 1205.76 cubic inches and a radius of 8 inches? Round to the nearest tenth of a
Anit [1.1K]
Cylinder height = volume / PI * radius^2
cylinder height =1,205.76 / PI * 8^2
cylinder height = <span> <span> <span> 5.9969582557 </span> </span> </span>
which I guess can be safely rounded to 6 inches
Source www.1728.com.diamform.htm


3 0
3 years ago
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