Find the range for the function k(n) = 2n2 when D = {–2, 1, 3}. R = {2, 8, 18} R = {2, 18, 36} R = {4, 12, 27} R = {4, 12, 16}
lianna [129]
K(n) = 2n^2.....where domain (n) = -2
k(-2) = 2(-2^2) = 2(4) = 8
k(n) = 2n^2.....where n = 1
k(1) = 2(1^2) = 2(1) = 2
k(n) = 2n^2...where n = 3
k(3) = 2(3^2) = 2(9) = 18
so ur range k(n) = { 2,8,18}
Answer:20
Step-by-step explanation:
25% is 1/4 so multiply 5 times 4
I think u should pit the number right?
\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]
Answer:
2/12
Step-by-step explanation:
7/12 -5/12 = 2/12
the number 2 can go into 2 once and 12 six times so you should get 1/6 as your answer