Is it supposed to be a attached picture to the question?
The equation of a line in the slope intercept form is expressed as
y = mx + c
Where
m represents slope
c represents y intercept
The equation of the given line is expressed as
3x - 6y = 30
Rearranging it so that it will look like the slope intercept form, it becomes
6y = 3x - 30
Dividing both sides by 6, it becomes
6y/6 = 3x/6 - 30/6
y = x/2 - 5
Looking at the equation, slope, m = 1/2
If two lines are parallel, it means that they have equal slope. This means that the slope of the line parallel to the given line is 1/2
To determine the y intercept, c of the line passing through the point (4, - 9), we would substitute
x = 4, y = - 9 and m = 1/2 into the slope intercept equation. It becomes
- 9 = 1/2 * 4 + c
- 9 = 2 + c
c = - 9 - 2
c = - 11
By substtuting m = 1/2 and c = - 11 into the slope intercept equation, the equation of the line would be
y = x/2 - 11
Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
I=2,400×0.07
I=168
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