The point A is located in quadrant II
The coordinate of the origin is always (0,0)
Answer:
x ≤ 4
Step-by-step explanation:
6x + 3 ≤ 27 subtract 3 both sides
6x ≤ 24 divide 6 both sides
x ≤ 4 There's your answer
Answer:
1
Step-by-step explanation:
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
Answer:
tan θ = (√13)/3
Step-by-step explanation:
cosθ = 3/√22 = adj/hyp
third side of triangle has dimension
c = √((√22)² - 3²) = √13
tan θ = opp/adj = (√13)/3
