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2 years ago

Anyone have an aswer to this?

Mathematics

2 answers:

SOVA2 [1]2 years ago

6 0

Answer:

x = ±√11 +2

Step-by-step explanation:

I know its right I am certain.

KIM [24]2 years ago

4 0

X/1 would equal -2- square root of 11 and x2 would equal -2 plus square root of 11

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Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

• cos2x

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$

$\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}$

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

3 0

1 year ago

A campground says campers can rend a square space taking up 225 square feet. How long would one side of the space be?

Helga [31]

Answer:

56.25 ft

Step-by-step explanation:

It is simple, since it is a square the sides are all the same length so you take A=area and divide it by four= h or w or l (height, width, length) so

225/4=56.25

3 0

2 years ago

Find X.............

Mrrafil [7]

Your answer is x = 78! Hope this helps!

3 0

2 years ago

All Major League Baseball stadiums use standard measurements for their infield area. The pitcher's mound is a circle with a diam

denis-greek [22]

Answer:

254 4/7 or 254.34 ft² (it depends on which method you use.)

Step-by-step explanation:

To find the area of a circle, the formula is πr².

I'll use both 22/7 and 3.14 as pi, so I'll end up with two different answers. Just choose the more reliable one.

22/7 version:

22/7 * 9^2

22/7 * 81/1

1782/7

254 4/7 ft²

3.14 version:

3.14 * 9^2

3.14 * 81

314 - (3.14 * 19)

314 - 62.8 + 3.14

251.2 + 3.14

254.34 ft²

As I said, I ended up with two different answers. You also had said not to round my answer, so the 22/7 version has a mixed number.

5 0

3 years ago

F(b)-f(a)

luda_lava [24]

Nooooooooooooooooooooooooooooooooooo

8 0

2 years ago