The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
Answer:
Step-by-step explanation:
y = 6x − 4
y = 5x − 3
A: chose a value for x(input) and get the out put (y) because the equation already in the slope intercept mode:y=mx+b
x y=6x-4 y=5x-3
1 y=2 y=2
2 y=8 y=7
0 -4 -3
slope :
y=6x-4 slope is 6 y intercept(0,-4)
y=5x-3 slope is 5 y intercept (0,-3)
solution of the pair of equation is the point of intersection :
6x-4=5x-3
6x-5x=-3+4
x=1 and y=6x-4 ⇒ y=6-4=2
<h2>(1,2)</h2>
Answer:
a = 120 cm²
Step-by-step explanation:
n = number of sides
edge length
40/n
divide the polygon into n congruent triangles
a = (1/2)(edge * apothem) * number of triangles
a = (1/2)(40/n)(6) * n
n cancels out
a = (1/2)(40)(6)
a = 120 cm²