If you are adding something to the water the concentration of water would drop, as it would start off as 100% water but then with the addition of another substance it would change that from 100% free to x% free, due to the water dissolving the substance.
The correct answer is: A checkpoint will be activated if the spindle does not attach to a kinetochore.
Prokaryotes, do not undergo mitosis (like eukaryotes) and therefore have no need for a mitotic spindle. Prokaryotes also don’ t have checkpoints foor the regulation of cell division.
Normal eukaryotic cells (unlike cancer cells), move through the cell cycle in a regulated way in order to make sure that cells don't divide under conditions that are unfavorable for them. Information about their own internal state (nutrients, signal molecules, DNA integrity) is signal to go or not to go through the cell division. Because of that there are few checkpoints in the cell cycle at which the cell examines the signals and makes a “decision”. The major checkpoints are:
• The G1- the first point at which it must choose, once it passes the G1 checkpoint the cell enters S phase
• The G2-the cell checks DNA integrity and checks if replication is done well.
• The spindle checkpoint-at the transition from metaphase to anaphase.
Active transport, specifically phagocytosis
Answer:
The answer to the given question out of the four options provided is given by:
Option a. Hydrolysis products are more resonance stabilized.
Explanation:
The answer selection to the above question can be justified as Phosphoanhydride on hydrolysis releases free high energy as the bonds formed by phosphoanhydride are the bonds with high energy.
Therefore, the product of hydrolysis after releasing this energy is more resonance stabilized.
<span>There is more sugar on side B the water to sugar ratio is lower so the water from side A will balance out the ratios between side A and B by moving across the membrane because </span>the sugar molecules cannot diffuse through the membrane, the water has to go to the sugar, therefore, we have to lower the concentration of the sugar.
