Question

Determine the energy in joules of a photon whose frequency is 3.55 x 10 to the 17 power Hz.

Answer 1

Answer:

E = 23.54 ×10⁻¹⁷ j

Explanation:

Given data:

Frequency = 3.55 ×10¹⁷ Hz

Energy of photon = ?

Solution:

Formula:

E = h. f

E = energy of photon

h = plancks constant (6.63×10⁻³⁴ Kg.m²/s)

f = frequency of photon

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Kg.m²/s × 3.55 ×10¹⁷ Hz

Hz = s⁻¹

E = 6.63×10⁻³⁴ Kg.m²/s × 3.55 ×10¹⁷ s⁻¹

E = 23.54 ×10⁻¹⁷Kg .m²/ s²

Kg .m²/ s² = j

E = 23.54 ×10⁻¹⁷ j