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Alenkinab [10]
3 years ago
8

Help me this is really hard

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0
1. 2n > 17

n > 7

2. n/5 ≥ 11

n ≥ 55

3. -3y ≤ -18

y ≥ 6

If these are right, please leave a thanks and a rating.
You might be interested in
Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)). (1 point)<br><br><br> −7<br> −3<br> 10<br> 33
qwelly [4]
Since the expressions for f(x) and g(x) are already given, f(g(2)) means to substitute the value of 2 to the expression of g(x), then further substituting the obtained value of g(2) into the expression of f(x). This is shown below:

f(x) = x + 8
g(x) = x^2 - 6x - 7

f(g(x) = x^2 - 6x - 7 + 8 
f(g(2)) = 2^2 - 6(2) + 1
f(g(2)) = 4 - 12 + 1
f(g(2)) = -7

Therefore, the correct answer is -7.
6 0
3 years ago
I need help on this one
Ivan
All planes without a plane DIH.
Answer:
BGH; CDA; FID; FIH

8 0
3 years ago
10^2+12^2+14^2+......+26^2=??
Kazeer [188]

Answer:

3156

Step-by-step explanation:

  • <em>Used formula:</em>
  • <em>(1² + 2² + 3² + ... + n²) =1/6*n(n + 1)(2n + 1)</em>

--------

  • 10²+12²+14²+......+26² =
  • (2*5)²+(2*6)² + (2*7)² + ... + (2*13)² =
  • 4*(5²+6²+7²+...+13²) =
  • 4*(1²+2²+...+13² - (1²+2²+3²+4²)) =
  • 4*(1/6*13(13+1)(2*13+1) - (1+4+9+16)) =
  • 4*(1/6*13*14*27- 30) =
  • 4*(819 - 30) =
  • 4*789 =
  • 3156
3 0
4 years ago
Base your answer on Betty is thinking of two consecutive integers whose sum is 41.
mel-nik [20]

Answer:

let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )

sum = 41

so, x + ( x + 1 ) = 41

      x + x + 1 = 41

        2x + 1 = 41

             2x = 41 -1 = 40

              2x = 40

                x = 40/2 = 20

x = 20

x + 1 = 20 + 1 = 21

so the consecutive numbers whose sum is 40 are, 20 and 21  

hope this answer helps you.....

please mark as brainliest... thank you!

6 0
3 years ago
Arturo, Pedro y Jorge son hermanos y duermen en la misma habitación. Su padre compró pintura para que entre los tres pinten su c
mr Goodwill [35]

Answer:

Tanto Pedro como Jorge deberán pintar 1/4 de la habitación cada uno.

Step-by-step explanation:

Dado que el cuarto entero es igual a 1, y que Arturo por ser el mayor de los hermanos tiene que pintar 1/2 de él, la parte que falta pintar es igual a 1/2 restante.

De ese 1/2, los hermanos menores, Pedro y Jorge, deben pintar dicha fracción en partes iguales. Por lo tanto, dado que (1/2) / 2 es igual a 1/4, la fracción que tanto Pedro como Jorge deberán pintar es de 1/4 de la habitación.

4 0
3 years ago
Read 2 more answers
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