WILL UPVOTE!<br> Factor the expression.<br> 4r^2 − 49 =

What is two solutions for x>6

Daniel [21]

7>6

8>6

9>6

etc.

Possible values for x:

x=7

x=8

x=9

etc.

4 0

3 years ago

jamal completed his math homework in 2/3 of an hour and his reading homework in 3/5 of an hour. How much time did it take him to

Assoli18 [71]

Answer:

Step-by-step explanation: We have to add how much time it took him to do all of his homework. To do this, we have to add 2/3 and 3/5.

First, we have to find a LCM between 3 and 5.

The LCM between those numbers are 15.

Next we find out what number to multiply 3 by to get 15, we multiply it by 5.

2 * 5 = 10

3 * 5 = 15

Next we find out what number to multiply 5 by to get 15, we multiply it by 3.

3 * 3 = 9

5 * 3 = 15

10/15+9/15=19/15

We are left off with 1 4/15

So it took him 1 hour and 4/15 minutes to do his homework.

3 0

3 years ago

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi

Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = $\sqrt{npq}$

$= \sqrt{np(1-p)}$

$= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3$

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

8 0

3 years ago

Help please please help

Semenov [28]

Answer:

Step-by-step explanation:

1,8

5,7

2,3

3 0

3 years ago

Read 2 more answers

Water flows through a pipe at a rate of 710 pints per day. Express this rate of flow in cubic feet per month. Round your answer

Snowcat [4.5K]

Answer:

356 ft³ per month.

Step-by-step explanation:

From the question,

Water flows at a rate of 710 pints per day.

We shall convert 710 pints to cubic feet (ft³).

This can be obtained as follow:

1 pint = 0.0167 ft³

Therefore,

710 pints = 710 × 0.0167 = 11.857 ft³

From the calculations made above, 710 pints is equivalent to 11.857 ft³.

Thus, we can say that water flows at a rate of 11.857 ft³ per day.

Finally, we shall determine the rate of flow of water in cubic feet per month.

Note: there are 30 days in a month.

Water flow at a rate of 11.857 ft³ per day.

Therefore, the rate of flow of water in 30 days will be = 30 × 11.857 ft³ = 356 ft³

Thus, the flow rate of water is 356 ft³ per month.

3 0

3 years ago

WILL UPVOTE! Factor the expression. 4r^2 − 49 =