-23
2x+2y/2w+3z
2(-5)+2(8)/2(-2)+3(-3)
-10+16/-4-9
-14-9
-23
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
False
Step-by-step explanation:
We first write the equation in the form ax² + bx + c=0 which gives us:
3x² - 6x + 9=0
Given the quadratic formula,
x= [-b ±√(b²- 4ac)]/2a ,the discriminant proves whether the equation has real roots or not.
The discriminant, which is the value under the root sign, may either be positive, negative or zero.
Positive discriminant- the equation has two real roots
Negative discriminant- the equation has no real roots
Zero discriminant - The equation has two repeated roots.
In the provided equation, b²-4ac results into:
(-6)²- (4×3×9)
=36-108
= -72
The result is negative therefore the equation has no real solutions.
