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tia_tia [17]
3 years ago
13

Plz help me sovle this4(-2 1/3) + 7 1/6

Mathematics
2 answers:
Radda [10]3 years ago
8 0
4(-21/3)+71/6
-91/3+71/6
-21/6
docker41 [41]3 years ago
4 0

Answer:

-2 1/6

Step-by-step explanation:

4(-2 1/3) + 7 1/6

-9 1/3 + 7 1/6

-2 1/6

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Send answers I will check if correct
Vikentia [17]

Step-by-step explanation:

x = n of years of mary

x+8= n of years of her bro

So her brother is (x+8)/x times as old as Mary

7 0
3 years ago
At how many different times will the digit 7 appear on a digital clock in 24 hours?(show your work and explain your strategy bel
exis [7]
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4 years ago
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expec
Sholpan [36]

Answer:

The degrees of freedom for the chi square statistic is 7-4=3

3 0
3 years ago
I can't seem to figure out number 13, with the star. I just don't know! Help is very appreciated ☺️
katrin2010 [14]
Given:
Scale of the map 1 1/4cm : 8 yards
Rectangular Park:  width : 2 1/2 cm ; length : 6 1/4 cm
Circular Pond: pi = 3.14 ; diameter 1 1/4 cm

Convert mixed factions into fractions.
Scale 1 1/4 = (4*1+1)/4 = 5/4
Width: 2 1/2 = (2*2+1)/2 = 5/2
Length: 6 1/4 = (4*6+1)/4 = 25/4
Diameter: 1 1/4 = (4*1+1)/4 = 5/4

width / scale * 8 yds = width in yards
5/2 ÷ 5/4 = 5/2 * 4/5 = 20/10 = 2 * 8 yds = 16 yds
length / scale * 8 yds = length in yards
25/4 ÷ 5/4 = 25/4 * 4/5 = 100/20 = 5 * 8 yds = 40 yds

Area of a rectangular park = l * w = 40 yds * 16 yds = 640 yds² 
 
diameter / scale * 8 yds = diameter in yards
5/4 ÷ 5/4 = 5/4 * 4/5 = 20/20 = 1 * 8 yds = 8 yds.

radius = d/2 = 8/2 = 4
Area of a circular pond = πr² = 3.14 * 4² = 3.14 * 16yds² = 50.24 yds²

5 0
3 years ago
HELP ASAP I WILL GIVE BRAINLIEST!!
Alexxx [7]

Consider the function F(x)= x³ +½x² −2x +3. Use calc and algebra to find any and all stationary points on the graph of the function.Precalc need help ASAP

Solution:

the above function has more than one root or more than one solution. The derivative of the function represents the slope of the tangent line to the curve

F(x)= x³ +½x² −2x +3, F'(x) = 3(x3-1)+(1/2)(2)(x2-1)-2(x1-1)+0

F'(x)=3x2+x-2 is the slope of the tangent line

setting the slope =0 and solving the quadratic equations, you find all the

critical points of interest

3x2+x-2=0, solve by factoring (3x-2)(x+1)=0, then 3x-2=0, x= 2/3

and x+1=0, x=-1 substituting these values of x in the original equation

you get the corresponding values of F(x) such that;

F(x)= x³ +½x² −2x +3, F(x)=(2/3)3+1/2(2/3)2-2(2/3)+3

= 8/27+4/18-4/3+3 = 8/27+2/9-4/3+3/1 = 59/27 and the first point is

(2/3, 59/27)

F(x)= x³ +½x² −2x +3, F(x)=(-1)3+1/2(-1)2-2(-1)+3

= -1+1/2+2+3 = 9/2 and the 2nd point is ( -1, 9/2)

these two points represents points where the slope of the tangent line to the curve is 0 and could be either maximum or minimum points

You can also find the y intercepts where x = 0 F(x)= x³ +½x² −2x +3, setting x = 0, y= F(x)=3 and the point ( 0,3) is a y intercept setting y = 0, then x intercepts can be found upon solving the equation x³ +½x² −2x +3 =0

3 0
2 years ago
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