You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
This is an addition problem.
Rearrange the given equations as
<span>+ f(x)=5x-2
+g(x)=2x+1
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Add up each column, as follows: (f+g)(x) = 7x - 1 (answer)</span>
First answer is 7.1 and second answer is 6.2
