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MA_775_DIABLO [31]
3 years ago
12

an 8-ounce serving of apples contains 8% of your daily vitamin c. how many ounces of apples would you need to get 100% of your d

aily vitamin c

Mathematics
2 answers:
kvasek [131]3 years ago
4 0
You need 100 ounces of apples
Goshia [24]3 years ago
3 0
You would need 100 ounces of apples.

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Select the best answer for the question 36-0.0058=
Yuri [45]
Considering this is a reasonably solvable math problem, I will subtract 0.0058 from 36 and an answer choice should match.
36.0000 - 0.0058 = 35.9942

Your answer is 35.9942.

I hope this helps!
4 0
4 years ago
A total of 202 tickets were sold for a theatre showing. If child tickets cost $6 and adult tickets cost $10, how many tickets of
polet [3.4K]

Answer:

167 adult tickets were sold

35 children tickets were sold

Step-by-step explanation:

Let the number of adult tickets be x

Let the number of children tickets be y

Total number of each ticket sold;

x + y = 202 equation 1

Total cost of the tickets

10x + 6y = 1708 equation 2

Let

x= 202 - y equation 3

Substitute 3 into 2

10(202 - y) + y = 1708

2020 - 10y + y = 1708

-9y = 1708 - 2020

-9y = -312

y= 35

Substitute y =35 into 1

x + 35 =202

x= 202 - 35

x= 167

Therefore;

167 adult tickets were sold

35 children tickets were sold

3 0
3 years ago
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Ierofanga [76]
The correct answer is the second option, Garcia, Woods, Ells , and Kelly.


8 0
3 years ago
A road crew can repave 1/56 miles of road each hour. They must repave a road that is 7/8 miles long. How long will it take the c
elixir [45]

7/8 miles = 49 / 56 miles so it will take the road crew 49 hours to repave the road.

6 0
3 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
Read 2 more answers
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