The answer is 16 because (-2*-2*-2*-2= 16)
Answer:
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
Step-by-step explanation:
Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
So, we need to remove any one (0, –2) or (0, 8) to make the relation a function. hope this helps you :) god loves you :)
Answer:
Age= 15
Step-by-step explanation:
Let a be for age at the moment
(a-3)^2 =6(a+9)
a^2-6a+9=6a+54
a^2-12a-45
(a-15)(a+3)
a=15 or a=-3
Age cannot be negative (-)
Therefore
Age =15
Answer:
The correct answer is D. It is not true that cluster sampling uses randomly selected clusters and samples everyone within each cluster.
Step-by-step explanation:
Cluster sampling is a method of collecting samples and statistical data, by means of which a certain group formed by people, things, events, etc., is taken as a sample, which are not considered individually but as part of a whole, which is in turn a proportional representation of the universality of samples available in the field.
Now, since this type of sampling allows to embrace large groups of sample units, data are not always obtained from all the components of the cluster, but from those necessary to be able to quantify the desired statistics.
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
