<h3>
Answer: 12/25</h3>
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Reason:
60% = 60/100 = 0.6 is the probability of making any given free-throw.
1 - 0.6 = 0.4 is the probability of missing any given free-throw.
We have these probabilities
- A = P(making 1st, missing 2nd) = 0.6*0.4 = 0.24
- B = P(missing 1st, making 2nd) = 0.4*0.6 = 0.24
The probability of making exactly one free throw is A+B = 0.24+0.24 = 0.48
Convert this to a fraction:
0.48 = 48/100 = (4*12)/(4*25) = 12/25
200+30+0.2+0.05+0.001=230.251
When the equation is ax+b which is y =ax+b
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
We meet again
so first divide 60 by 5
this gives 12
then multiply 12 by 4
giving a final answer of 48
