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3 years ago

Can someone please help with this?

Mathematics

2 answers:

Alex Ar [27]3 years ago

5 0

Answer:

Answer for x = 5

Step-by-step explanation:

√5x +11 - 1 = x We isolate

-√5x+11 = -x-1 We tidy up

√5x+11 = x+1 We raise both sides to second power

(√5x+11)2 = (x+1)2 After brackets we show after squaring

5x+11 = x2+2x+1 We rearrange the order

x2 - 3x -10 = 0 We count the roots = 2

{x1, x2}={5, -2} We show the roots and show original equation, where the root is isolated, after tidy up

√5x+11 = x+1 Plug in 5 for x as x =5

√5•(5)+11 = (5)+1 Then simplify

√36 = 6 Solution checks !!

Solution is:

x = 5

Original equation, root isolated, after tidy up

√5x+11 = x+1 Plug in -2 for x

√5•(-2)+11 = (-2)+1 Simplify

√1 = -1 Solution does not check

1 ≠ -1

Answer for x = 5

IrinaVladis [17]3 years ago

3 0

Answer:

x= -2, x = 5

Step-by-step explanation:

$\sqrt{5x+11}-1=x$

$\sqrt{5x+11}=x+1$

$5x+11=(x+1)^2$

$5x+11=x^2 + 2x + 1$

$0=x^2 + 2x + 1-5x-11$

$0=x^2 -3x-10$

$0=(x+2)(x-5)$

x= -2, x = 5

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NeX [460]

Answer:

(a)

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