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nikitadnepr [17]

3 years ago

15

How to find the pair solution to the equation

1 answer:

yulyashka [42]3 years ago

3 0

Answer:

To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation.

Step-by-step explanation:

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Which of the following is true?

EleoNora [17]

The options can be rewrited as follow:
A. 5<4
B. 5<5
C. 5<4
D. 4<-5

∴ Answer is none of the above.

Unless perhaps you have written down the question incorrectly.

8 0

3 years ago

What makes (a + 2)(b – 9) = 0 true?

prohojiy [21]

B would have to equal 9 and a should equal -2 to get 0

5 0

3 years ago

Read 2 more answers

BRAINLIEST!!! Plz help ASAP

Svetllana [295]

Answer: R = (4, 5)

Step-by-step explanation: Midpoint is simply the center of a line. So, the equation for it is ((x1+x2)/2, (y1+y2)/2). Hence for this,

x coordinate- (6+x)/2=5

x=4

y coordinates- (9+y)/2=7

y=5

And therefore R is (4, 5)

6 0

3 years ago

A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the

Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

$P(A) = 0.90*0.03 + 0.1*0.97 = 0.124$

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

$P(A \cap B) = 0.9*0.03 = 0.027$

What is the conditional probability that she does, in fact, have the disease

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177$

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0

3 years ago

The average height of two forwards

Gelneren [198K]

Answer:

the other 2 guards must be 6 feet 3 inches

Step-by-step explanation:

$\frac{3(6.8)+2x}{5} =6.6$

5 0

3 years ago