If AB = BC then set up the equation 3x - 4 = 5x - 10
Subtract 3x.
-4 = 2x - 10
Add 10.
6 = 2x
Divide by 2.
3 = x
AB is 3x - 4 so
3(3) - 4
9 - 4
5.
AB = 5
If AB is not equal to BC then this is not solvable.
But if they are I am sure AB = 5.
Hope this helps
Answer:
7
Step-by-step explanation:
1/7+1/3= 3/21+7/21= 10/21= 0.476190
the 6 digits after the decimal point get repeated
6*3= 18- three full cycles and the second digit after 3 cycles = 7 so the 20th digit is 7
Answer:
(0, -5), (4, -2), (-16, -17)
Step-by-step explanation:
I attach your full question in the image below
The equation is
3x-4y-8=12
Which can be rewritten as
3x-4y =12 +8
3x-20 = 4y
y = (3/4)*x - 5
We need to check each individual case
(0,-5)
y = (3/4)*(0) - 5
y = -5
True
(4,-2)
y = (3/4)*(4) - 5
y = -2
True
(8,2)
y = (3/4)*(8) - 5
y = 1
False
(-16,-17)
y = (3/4)*(-16) - 5
y = -17
True
(-1,-8)
y = (3/4)*(-1) - 5
y = -23/4
False
(-40,-34)
y = (3/4)*(-40) - 5
y = -35
False
(0,-5) (4,-2) and (-16,-17) are the solutions
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer:
Step-by-step explanation:
4x = 60
60/4 = 15
width : 15
length: 45