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nikitadnepr [17]
3 years ago
15

How to find the pair solution to the equation

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0

Answer:

To figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation.

Step-by-step explanation:

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AABC is isosceles.<br> AB = 3x - 4 and BC = 5x - 10.<br> AB = [?]
Schach [20]

If AB = BC then set up the equation 3x - 4 = 5x - 10

Subtract 3x.

-4 = 2x - 10

Add 10.

6 = 2x

Divide by 2.

3 = x

AB is 3x - 4 so

3(3) - 4

9 - 4

5.

AB = 5

If AB is not equal to BC then this is not solvable.

But if they are I am sure AB = 5.

Hope this helps

4 0
3 years ago
What is the 20th digit after the decimal point of the sum of the decimal equivalents for the fractions $\frac{1}{7}$ and $\frac{
Afina-wow [57]

Answer:

7

Step-by-step explanation:

1/7+1/3= 3/21+7/21= 10/21= 0.476190

the 6 digits after the decimal point get repeated

6*3= 18- three full cycles and the second digit after 3 cycles = 7 so the 20th digit is 7

5 0
3 years ago
Which points of the following points are solutions to the equation 3x-4y-8=12
Natali [406]

Answer:

(0, -5), (4, -2), (-16, -17)

Step-by-step explanation:

I attach your full question in the image below

The equation is

3x-4y-8=12

Which can be rewritten as

3x-4y =12 +8

3x-20 = 4y

y = (3/4)*x - 5

We need to check each individual case

(0,-5)

y = (3/4)*(0) - 5  

y = -5

True

(4,-2)

y = (3/4)*(4) - 5  

y = -2

True

(8,2)

y = (3/4)*(8) - 5  

y = 1

False

(-16,-17)

y = (3/4)*(-16) - 5  

y = -17

True

(-1,-8)

y = (3/4)*(-1) - 5  

y = -23/4

False

(-40,-34)

y = (3/4)*(-40) - 5  

y = -35

False

(0,-5) (4,-2) and (-16,-17) are the solutions

8 0
3 years ago
Several intervals can be combined into one region using the "set union" operation, ∪∪, which is represented as "u" in webwork. f
alekssr [168]

Write the set of points from  -6 to 0 but excluding  -4  and 0 as a union of intervals

First we take  the interval  -6 to 0. In that -4  and 0 are excluded.

So we split the interval -6 to 0.

Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.

Interval becomes [-6,-4) . It says -6 included but -4 excluded.

Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets

(-4,0)

Now we take union of both intervals

[-6,-4) U (-4,0)  --- Interval from  -6 to 0 but excluding  -4  and 0



7 0
3 years ago
Nool
larisa [96]

Answer:

Step-by-step explanation:

4x = 60

60/4 = 15

width : 15

length: 45

4 0
2 years ago
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