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3 years ago

If Y varies directly as X and Y= 79 when X= 49, Find Y if X = 9

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

y = 14.5

Step-by-step explanation:

given that y varies directly as x

mathematically,

y ∝ x

y = kx .............................................. where k is the constant of proportionality.

k = y /x

given that

y = 79

x = 49

k = 79/49

k = 1.61

to find y when x = 9

from

y = kx

y = 1.61 × 9

y = 14.5

therefore the value of y when x = 9 in ths variation is evaluated to be equals to 14.5

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How to write sixty nine million seventeen thousand four hundred nine

sweet-ann [11.9K]

69,017,409 is the correct answer

6 0

3 years ago

Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t

Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53 is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) = 2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53 is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0

3 years ago

A strand of bacteria has a doubling time of 15 minutes. If the population starts with 10 organisms, how long would it take for t

slamgirl [31]

In 90 minutes the population to grow to 700 organisms.

Given that,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

We have to determine,

How long would it take for the population to grow to 700 organisms?

According to the question,

A strand of bacteria has a doubling time of 15 minutes.

If the population starts with 10 organisms.

In 15 minutes strand of bacteria has a doubling time the population starts with 10 organisms.

$\rm = 10 \times 2 = 20 \ bacteria$

In 15 minutes 20 bacteria for the population to grow.

In 30 minutes strand of bacteria has a doubling time the population starts with 20 organisms.

$\rm = 20 \times 2 = 40 \ bacteria$

In 30 minutes 40 bacteria for the population to grow.

In 45 minutes strand of bacteria has a doubling time the population starts with 40 organisms.

$\rm = 40 \times 2 = 80 \ bacteria$

In 45 minutes 80 bacteria for the population to grow.

In 60 minutes strand of bacteria has a doubling time the population starts with 80 organisms.

$\rm = 80 \times 2 = 160 \ bacteria$

In 60 minutes 160 bacteria for the population to grow.

In 75 minutes strand of bacteria has a doubling time the population starts with 160 organisms.

$\rm = 160 \times 2 = 320 \ bacteria$

In 75 minutes 320 bacteria for the population to grow.

In 90 minutes strand of bacteria has a doubling time the population starts with 320 organisms.

$\rm = 320 \times 2 = 640 \ bacteria$

In 90 minutes 640 bacteria for the population to grow.

In 120 minutes strand of bacteria has a doubling time the population starts with 640 organisms.

$\rm = 640 \times 2 = 1280 \ bacteria$

In 120 minutes 1280 bacteria for the population to grow.

Hence, In 90 minutes the population to grow to 700 organisms.

For more details refer to the link given below.

brainly.com/question/3188472

3 0

2 years ago

Read 2 more answers

-5=x/3-8 plz someone help me plz

Flura [38]

Isolate x by adding 8 to both sides.
3 = x/3
Then, multiply by 3 on both sides.
9 = x
To prove that this is right, you can imput 9 into the equation and it equals -5.

5 0

2 years ago

How many different 6-letter arrangements are possible using the letters in ALTUVE?

marshall27 [118]

The answer is 32 because there are 5 in the actual one

6 0

3 years ago