Answer:
Step-by-step explanation:
The product of two numbers is always rational.
Find values of c and d that satisfy each of the following equations. (There may be more than one correct answer.)
1 answer:
Answer:
The given equations have no solution.
Step-by-step explanation:
The given equations are
1. cd = 0
2. (c − 5)d = 2
3. (c − 5)d = 0
4. (c − 5)(d + 3) = 0
From the given equations it is clear that left side of equation (2) and (3) are same but right side of the equation are not same, which not possible for any values of c and d.
The second equation is
Using equation (3), substitute the (c-5)d=0 in the above equation.
The above statement is false because we know that .
Therefore, the given system of equations have no solution.
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Option 1
To find the y-intercept of a quadratic that is in factor formed follow the steps below:
First take the factor form and put it into standard quadratic form
Standard quadratic form:
To put the the factor form of a qudratic into standard form, we use the foil method
(x-6)(x-2) =
Now to find the y-intercept, input 0 where the x is located:
y-intercept = (0,12)
Why did I use 0? Remember the y-intercept is where the line crosses the y axis so this means the x value of the y intercept is always = 0. Also, not, to find the y-intercept, you could of just multiplied the 6 and 2 in the factored form to get the 12 and since you know that the x is always 0 at the y-intercept, you know that the y-intercept is at (0,12)
Option 2
Input 0 for x in f(x) = (x-6)(x-2)
f(x) = (x-6)(x-2)
f(0) = (0 - 6)(0 - 2)
f(0) = (6)(2) = 12
x = 0
f(0) = y = 12
y-intercept = (0,12)
To find the y-intercept of a quadratic that is in factor formed follow the steps below:
First take the factor form and put it into standard quadratic form
Standard quadratic form:
To put the the factor form of a qudratic into standard form, we use the foil method
(x-6)(x-2) =
Now to find the y-intercept, input 0 where the x is located:
y-intercept = (0,12)
Why did I use 0? Remember the y-intercept is where the line crosses the y axis so this means the x value of the y intercept is always = 0. Also, not, to find the y-intercept, you could of just multiplied the 6 and 2 in the factored form to get the 12 and since you know that the x is always 0 at the y-intercept, you know that the y-intercept is at (0,12)
Option 2
Input 0 for x in f(x) = (x-6)(x-2)
f(x) = (x-6)(x-2)
f(0) = (0 - 6)(0 - 2)
f(0) = (6)(2) = 12
x = 0
f(0) = y = 12
y-intercept = (0,12)