Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
-4r-11=4r+21
Move 4r to the other side
Sign changes from +4r to -4r
-4r-4r-11=4r-4r+21
-4r-4r-11=21
-8r-11=21
Move -11 to the other side
Sign changes from -11 to +11
-8r-11+11=21+11
-8r=21+11
-8r=32
Divide both sides by -8
-8r/-8=32/-8
Answer: r=-4
The answer should be AC+BC
We can answer this by applying the rule called "Greater angle, greater side". This is where in any triangle, the opposite side of the larger angle is also longer.
So in this question, first we have to find the largest 2 angles, which is ∠ABC and ∠BAC with measures of 120° and 35° respectively. Therefore, from the diagram, the opposite sides of the angles are AC and BC.
Therefore, the answer should be AC+BC.
Answer:
1. -3 on both side and m=4
2. +2 on both side and k=10
3. divide 3 on both side and n=6
