All categories

3 years ago

To hard for me to do need help please

Mathematics

2 answers:

siniylev [52]3 years ago

4 0

Answer:

$3(2)+6=12$

Step-by-step explanation:

just replace x by 2

Vsevolod [243]3 years ago

3 0

Answer:

Step-by-step explanation:

Given,

x = 2

To find :

The value of 3x + 6 = ?

Solution,

Substitute x = 2 in " 3x + 6 ",

3x + 6

= 3 ( 2 ) + 6

= 6 + 6

= 12

You might be interested in

Pleassssssseeeeee hhheeelllppp

elena-s [515]

A= -2+(-3)×(-8+4)

-2+(-3)×(-4)

-2+12=10

B=-9+8×7+(-12)

-9+56-12=35

C=8-2= -4

D=8÷2=4

E= -4-35= -39

F=153

8 0

4 years ago

Unit Rate is a ratio where the second term of the ratio is ONE. TRUE or FALSE

Papessa [141]

Answer:

True

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which property states that the order of the addends does not affect the sum? commutative property of addition reflexive property

Nonamiya [84]

Answer:

Commutative property

Step-by-step explanation:

Commutative property states that no matter how the addens are placed, the result of the operation (sum) remains the same.
For example, given three numbers a, b and c, the result of $a+b+c=b+c+a=a+c+b$ .
Then, when you are solving a sum, the order of the elements does not matter. If we want to see this numerically, with an other example: $4+5=5+4=9$ .

4 0

3 years ago

Read 2 more answers

Let X have the uniform distribution U(0, 2) and let the conditional distribution of Y , given that X = x, be U(0, x). Find the j

Elina [12.6K]

Answer:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

Step-by-step explanation:

We have two random variables X and Y. $X \sim Unif(0,2)$ and given that X=x, Y has uniform distribution (0,x)

From the definition of the uniform distribution we have the densities for each random variable given by:

$f_X (x) =\frac{1}{2} , 0\leq x\leq 2$

$f_{Y|X} (y|x) = \frac{1}{x}, 0\leq y \leq x$

And on this case we can find the joint density with the following formula:

$f(x,y) = f_{Y|X}(y|x) f_X (x)$

And multiplying the densities we got this:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

Now with the joint density we can find the expected value E(Y|x) with the following formula:

$E(Y|x) = \int y f_{Y|X}(y|x)dx$

And replacing we got:

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

5 0

4 years ago

Find angle prs and angle qrs

liubo4ka [24]

I really don’t know I’m just tryna get points but sorry

8 0

3 years ago