Answer:
b. 1010
Explanation:
As per question,two 4-bit binary one's complement numbers are given-
1110 and 1100
and we have to find the addition of them,
In <u>1</u>11<u>0</u>, the MSB(most significant bit) is 1 and LSB(least signifacnt bit) is 0,So we will start addition from LSB i.e 0.
In <u>1</u>10<u>0</u>, the MSB(most significant bit) is 1 and LSB(least signifacnt bit) is 0,So we will start addition from LSB i.e 0.
Starting from LSB TO MSB-
Add 0 of 111<u>0</u> with 0 of 110<u>0</u>
we will get 0, with no carry.
then check for the left of the previous
Add 1 of 11<u>1</u>0 with 0 of 11<u>0</u>0
we will get 1, with no carry.
then check for the left of the previous
Add 1 of 1<u>1</u>10 with 1 of 1<u>1</u>00
we will get 0, with 1 carry.
This carry is shifted to the left we will add it in addition of the two.
Add 1 of <u>1</u>110 , 1 of <u>1</u>100 and the left carry i.e-1.
we will get 1, with 1 carry.
So, finally we get 1 |1010, we will eliminate carry.
1010 will be the answer
