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Darya [45]
3 years ago
9

Someone please help.. You will receive lots of medals in the future because of people looking this question up and giving you me

dals
Matt did an experiment to study the solubility of two substances. He poured 100 mL of water at 20 °C into each of two beakers labeled A and B. He put 50 g of Substance A in the beaker labeled A and 50 g of Substance B in the beaker labeled B. The solution in both beakers was stirred for 1 minute. The amount of substance left undissolved in the beakers was weighed. The experiment was repeated for different temperatures of water and the observations were recorded as shown.

Part 1: Which, if any, substance is soluble in water?
Part 2: Explain how the data helped you determine solubility for both substances for temperatures 20 °C to 80 °C.

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0
Part 1: I'm pretty sure B is soluble in water.
Part 2: The data is showing that A isn't soluble at all (probably cause it's solid or a lipid or something) because the amount undissolved stays the same as B changes in solubility.
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Hello there!

Answer: ⇒ C. -30

_________________________________________________________

Step-by-step explanation:

First you had to remove parenthesis.

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Again apply absolute value.

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Hope this helps!

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