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NeTakaya
3 years ago
5

What is the difference of 11 and 3.5?​

Mathematics
2 answers:
choli [55]3 years ago
7 0
7.5
Take 3 away from 11 and then subtract .5
Deffense [45]3 years ago
6 0
7.5

Explanation:
11-3.5=
Take 3 away form 11 and then get 8 then subtract.5 and you are left with 7.5
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PLEASE HELP
stira [4]

Answer:

The values of x and y are x = 3 and y = 11

Step-by-step explanation:

The isosceles triangle has two equal sides in length, and its base angles are equal in measures

In ΔJKL

∵ ΔJKL is an isosceles triangle with vertex K

→ That means the equal sides are JK and KL

∴ JK = KL

∵ JK = 8x and KL = 13x - 15

→ Equate them

∴ 13x - 15 = 8x

→ Add 15 to both sides

∵ 13x - 15 + 15 = 8x + 15

∴ 13x = 8x + 15

→ Subtract 8x from both sides

∵ 13x - 8x = 8x - 8x + 15

∴ 5x = 15

→ Divide both sides by 5 to find x

∴ x = 3

∵ K is the vertex of the ΔJKL

∴ ∠KJL and ∠KLJ are the base angles

∵ The base angles are equal in measures

∴ m∠KJL = m∠KLJ

∵ m∠KJL = 5y - 3

∴ m∠KLJ = 5y - 3

∵ The sum of the measures of the angles of a Δ is 180°

∴ m∠KJL + m∠KLJ + m∠JKL = 180°

∵ m∠JKL = 76°

→ Substitute the measures of the 3 angles in the equation

∴ 5y - 3 + 5y - 3 + 76 = 180

→ Add the like terms on the left side

∵ (5y + 5y) + (76 - 3 - 3) = 180

∴10y + 70 =180

→ Subtract 70 from both sides

∵ 10y + 70 - 70 = 180 - 70

∴ 10y = 110

→ Divide both sides by 10 to find y

∴ y = 11

∴ The values of x and y are x = 3 and y = 11

5 0
2 years ago
What is the range of this relation?
riadik2000 [5.3K]
The range of the relation is 35,40,45,60,75
Reason being in relation range is the set of all second elements of ordered pairs (y-coordinates).
5 0
2 years ago
Tell me if i got number 2 wrong or right also answer the question
hichkok12 [17]

Answer:

I hope I know but I need help my self

4 0
2 years ago
What is 18% of 700? Enter your answer in the box.
ella [17]
18% of 700 is 126     .18x700=126
4 0
3 years ago
Read 2 more answers
a) Estimate the volume of the solid that lies below the surface z = 7x + 5y2 and above the rectangle R = [0, 2]⨯[0, 4]. Use a Ri
SSSSS [86.1K]

In the x direction we consider the m=2 subintervals [0, 1] and [1, 2] (each with length 1), while in the y direction we consider the n=2 subintervals [0, 2] and [2, 4] (with length 2). Then the lower right corners of the cells in the partition of R are (1, 0), (2, 0), (1, 2), (2, 2).

Let f(x,y)=7x+5y^2. The volume of the solid is approximately

\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy\approx f(1,0)\cdot1\cdot2+f(2,0)\cdot1\cdot2+f(1,2)\cdot1\cdot2+f(2,2)\cdot1\cdot2=\boxed{164}

###

More generally, the lower-right-corner Riemann sum over m=\mu and n=\nu subintervals would be

\displaystyle\sum_{m=1}^\mu\sum_{n=1}^\nu\left(7\frac{2m}\mu+5\left(\frac{4n-4}\nu\right)^2\right)\frac{2-0}\mu\frac{4-0}\nu=\frac83\left(101+\frac{21}\mu+\frac{40}{\nu^2}-\frac{120}\nu\right)

Then taking the limits as \mu\to\infty and \nu\to\infty leaves us with an exact volume of \dfrac{808}3.

7 0
3 years ago
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