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NeTakaya
3 years ago
5

What is the difference of 11 and 3.5?​

Mathematics
2 answers:
choli [55]3 years ago
7 0
7.5
Take 3 away from 11 and then subtract .5
Deffense [45]3 years ago
6 0
7.5

Explanation:
11-3.5=
Take 3 away form 11 and then get 8 then subtract.5 and you are left with 7.5
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PLEASE HELP ME OUT!!!
DedPeter [7]

Answer:

20/3  or  6.67  or  6 \frac{2}{3}  (any of these are correct)

Step-by-step explanation:

Volume of triangular pyramid formula is V = 1/3 * base area * height

V = 1/3 * 5 * 4 = 20/3

20/3  or  6.67  or  6 \frac{2}{3}

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2 years ago
If the sum of the interior angles is 720°, how many sides does the polygon have?
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6

Step-by-step explanation:

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What is the factored form of 27 - 530?
fenix001 [56]

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Step-by-step explanation:

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3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
Sneha is planning a 5-night vacation. It will cost $50 for transportation, $290 for food, and $95 per night for a hotel room. Sh
Goshia [24]

Answer:

Step-by-step explanation:

Total cost for trip = 290 + 50 + 95*5 =290+50+ 475 = $ 815

Savings = $143

Money needed = 815 - 143 = $ 672

No. of driveways = 672/48 = 14

14 driveways must she shovel to have enough money to pay for the trip.

6 0
3 years ago
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