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4 years ago

14

The measurement of 2 and justification

1 answer:

Minchanka [31]4 years ago

8 0

M<2=105. They must add up to 180.

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Don't understand question and don't know formula

zzz [600]

The formula is (number of sides-2)*180 over number of sides

Each angle for hexagon is 120degree because
(6-2)*180 over 6 equals to 120
So p is 120
For q:
2q=180-120
2q=60
q=60 over 2
q=30
P+Q=120+30
=150

7 0

3 years ago

Generate and solve another division problem with the same quotient and remainder as the two problems below.explain your strategy

Andrew [12]

Answer:

ITS AN ASSESMENT THIS VIOLATES THE HONOR CODE

Step-by-step explanation:

8 0

3 years ago

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A company that makes boxes finds that 3 out of 20 boxes are damaged. What percent of the boxes are damaged? ( I WILL GIVE BRAINL

noname [10]

Answer:

a.

Step-by-step explanation:

6 0

3 years ago

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If necessaly, combine like terms.<br> (3x+8)2

mel-nik [20]

Step-by-step explanation:

multiply 2 with the bracket numbers

6x+16=0

6x= - 16

x=-16/6

x= - 8/3

4 0

3 years ago

Simplify.Your answer should contain only positive exponents.

zhannawk [14.2K]

Step-by-step explanation:

1) $r^3r^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=r^{3+3}$

$=r^6$

2) $3k^3k^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=3k^{3+3}$

$=3k^6$

3) $\left(3b^2\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=3^3\left(b^2\right)^3$

$=27\left(b^2\right)^3$

$=27b^6$

4) $\left(2m^3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=2^3\left(m^3\right)^3$

$=8\left(m^3\right)^3$

$=8m^{3\cdot \:3}$

$=8m^9$

5) $\frac{3r^3}{r^2}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$=3r^{3-2}$

$=3r^1$

$=3r$

3 0

3 years ago