The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
<h3>What is a circle?</h3>
It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
Prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x² + y² = 5.
x = 2y + 5 ...1
x² + y² = 5 ...2
If the intersection of the point of the circle and line is one. Then the line is tangent to the circle.
Then from equations 1 and 2, we have
(2y + 5)² + y² = 5
4y² + 25 + 20y + y² - 5 = 0
5y² + 20y + 20 = 0
5y² + 10y + 10y + 20 = 0
5y (y + 2) + 10(y + 2) = 0
(5y + 10)(y + 2) = 0
y = -2, -2
Then the value of y is unique then the value of x will be unique.
The value of x will be
x = 2(-2) + 5
x = -4 + 5
x = 1
The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
More about the circle link is given below.
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-8, -19, -30, -49 , -60
<u>Step-by-step explanation:</u>
Here we have the following sequence :
-8, -19, -30, _ , _
- First term of sequence is -8 .
- Second term of sequence is -19 :
- Third term of sequence is -30 :
- Fourth term of sequence is :
- Fifth term of sequence is :
Following sequence was an AP( Arithmetic Progression ) with first term as -8 i.e. 
and common difference 
having general equation as : 
.
Answer:
Step-by-step explanation:
(2x-5)(x+2)
roots are 5/2 and -2
The.value of x woukd be 2
Answer: 4n
Step-by-step explanation:
