Answer:
Explained
Explanation:
Michelson contrast is used for patterns where the distribution of bright and dark segments is nearly equal.
It is given by:

where I_max = maximum illumination and I_min = minimum illumination
we know that
typically, I_min = 54% of I_max (general standard)
or I_min = 0.54 I_max
putting this value in above equation to get m
this approximately corresponds to m = 0.3 or 30%
hence, 30% recommended as the minimum Michelson contrast
H2 or H:H
hope this helps
Answer:
= 3,126 m / s
Explanation:
In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.
the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s
Before the crash
p₀ = m v₁₀ + M v₂₀
After the inelastic shock
= m
+ M
p₀ = 
m v₀ + M v₂₀ = m
+ M
We cleared the end of the train
M
= m (v₁₀ - v1f) + M v₂₀
Let's calculate
3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45
= (-3.9 + 8.82) /3.60
= 1.36 m / s
As we can see, this speed is lower than the speed of the car, so the two bodies are joined
set speed must be
m v₁₀ + M v₂₀ = (m + M)
= (m v₁₀ + M v₂₀) / (m + M)
= (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)
= 3,126 m / s
Answer:
Revolving velocity = 2 km/s
Explanation:
Velocity of circular motion = Radius x Angular velocity.
Angular velocity, ω = 2πf, where f is the frequency of circular motion.
Here frequency, f = 2 revolutions per minute
f =
revolutions per second.
Angular velocity, ω = 2πf = 0.209 radians/second.
Radius = 6 miles = 6 x 1.6 x 10³ = 9.6 x 10³ m.
Linear velocity = 9.6 x 10³ x 0.209 = 2006.4 m/s= 2 km/s
Revolving velocity = 2 km/s