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3 years ago

7

Which object is I’m equilibrium?

1 answer:

IrinaK [193]3 years ago

3 0

Equilibrium is a state of no motion. If donuts are on the table, they are in equilibrium. Literally anything that is NOT moving relative to the earth is in equilibrium. The chair is in equilibrium, the table is in equilibrium, the cookies are in equilibrium, and so on.

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How many neutrons does element X if it’s atomic number is 28 and its mass number is 87

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the answer is 59 neutrons

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True or False? When a pot of water is heated on a stove, it will begin to bubble. This is a sign that there was a chemical react

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3 years ago

Read 2 more answers

during a 3.00 s time interval,the runners position changes from x1=50.0m to x2=30.5m what was the runners average velocity

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7 0

3 years ago

A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:

34kurt

Answer:

a) $v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s$

The velocity increase by a factor of $\sqrt{2}$

b) $v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s$

The velocity decrease by a factor of 2.

c) $v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s$

The velocity increase by a factor of 2

d) $v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s$

The velocity not changes.

Explanation:

For this case we know that the velocity is $v = 200 cm/s = 2m/s$

$v_f$ represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

$v = \sqrt{\frac{T}{\rho}}$

And the linear density is defined as:

$\rho = \frac{m}{L}$

And if we replace this we got:

$v = \sqrt{\frac{TL}{m}}$

If the tension mass is doubled we have this:

$v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s$

The velocity increase by a factor of $\sqrt{2}$

Part b

If we mass is quadrupled we have this:

$v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s$

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

$v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s$

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

$v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s$

The velocity not changes.

7 0

3 years ago