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xenn [34]
3 years ago
14

Which side lengths form a right triangle?

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

B. 5, 12, 13

Step-by-step explanation:

√5²+12²=13 - yes

√4²+7²= 8.06- no

√20²+22²=29.73 - no

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A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th
NikAS [45]

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

4 0
3 years ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
A construction company completes two projects. The first project has $3,000 in labor expenses for 60 hours worked, while the sec
d1i1m1o1n [39]

Answer: 2,100 = 0.02(42) + b

2,100 = 50(42) + b

Step-by-step explanation: good day man

3 0
2 years ago
-4/3(3q-10) simplified
monitta

Answer:

Answer in the photo

Step-by-step explanation:

Just simplify the expression

4 0
3 years ago
Read 2 more answers
Help me to simplify; <br> log_{5} 12.5+log_{5}10
liq [111]

Answer:

15.726

Step-by-step explanation:

log 5=0.698×12.5

=8.737

=0.698×10

=6.989

=8.737+6.989

=15.726

8 0
3 years ago
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