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Oksi-84 [34.3K]

2 years ago

9

Parallelogram is 42squared height is 7m whats the base

2 answers:

Klio2033 [76]2 years ago

6 0

Answer:

<h2>6m</h2>

Step-by-step explanation:

Area of Parallelogram = Base × Height

and

Base = Area : Height

42 : 7 = 6m

ludmilkaskok [199]2 years ago

5 0

Answer:

6m.is the base

Step-by-step explanation:

have a great day ahead

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Does the table represent y as a function of x? justify your answer <br><br> pleaseee helpp!!

Leno4ka [110]

Answer:

No it doesn't.

Step-by-step explanation:

In order for y to represent a function of x, no two x values can have the same y values. Basically x causes y and if y is the same under two different x values then the table isn't true. You can also use the vertical line test to ensure you are correct. I may not be correct but I believe I am

6 0

3 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

2 years ago

I need help on how to solve this, it says these are not special right triangles

Tom [10]

The answer is ............................ go to school

6 0

3 years ago

Read 2 more answers

Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3

yawa3891 [41]

$\bf{1) \ x^4-61x^2+900=0 }$

Applying the factorization method, for example:

$\bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}$

$\bf{\\ &=(x+6)(x-6)(x+5)(x-5); }$

$\bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5 }$

$\bf{2) \ x^4-25x^2+144=0 }$

Applying the factorization method:

$\bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }$

$\bf{ =(x-4)(x+4)(x-3)(x+3); }$

$\bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3 }$

7 0

2 years ago

What are the factors of m2 – 12m + 20?

amm1812

M² - 12m + 20

m² ⇒ m * m
20 ⇒ - 10 * -2

(m - 10)(m - 2)
m(m - 2) - 10(m-2)
m² - 2m - 10m + 20
m² - 12m + 20

m - 10 = 0
m = 10

m - 2 = 0
m = 2

5 0

3 years ago

Read 2 more answers