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34kurt
3 years ago
5

The ages of commercial aircraft are normally distributed with a mean of 13.5 years and a standard deviation of 7.3 years. what p

ercentage of individual aircraft have ages greater than 15 ​years? assume that a random sample of 49 aircraft is selected and the mean age of the sample is computed. what percentage of sample means have ages greater than 15 ​years?
Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0
Answer: The percent higher is 41.68%. If 49 planes were selected, 20 of them should be above 15 years.

To find the percent, we first need the z-score.

(15 - 13.5) / 7.3 = 0.21

Now, use a normal distribution table to find the percent above a score of 0.21. It will be 41.68%.

To find the number of 49 planes above this value, multiply 49 by 0.4168. You will have about 20.4 planes.
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You solve for y

4y=-6x+2

y=-6/4x+2

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<h3><u>The value of x is greater than or equal to -4.</u></h3>

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5 0
3 years ago
Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 12. Use the empirical rule t
MissTica

Answer:

A) 99.7% of people have an IQ between 64 and 136.

B) 5% of people have an IQ score less than 76 or greater than 124.

C) 16% of people have an IQ score greater than 112.

Step-by-step explanation:

The Empirical Rule tells us that, in a normal or 'bell-shaped' distribution, 68% of the data is one standard deviation from the mean, 95% of the data is two standard deviations from the mean, and 99.7% of the data is three standard deviations from the mean.

A) 64 and 136 are 3 standard deviations away from the mean, so 99.7% of people have an IQ between 64 and 136.

B) 76 and 124 are 2 standard devations away from the mean, but the answer is asking what percentage is not between them. 100% - 95% gives us 5%.

C) 112 is one standard deviation away from the mean. If we want to find the percentage greater, then we can do 100% - 50% (as 112 is to the left of the mean), then we can take half of 68 to get 34%, and after subtracting 50% and 34% from the 100%, we get 16%.

8 0
3 years ago
How do you solve 58 and 1/3÷6 and 2/3
strojnjashka [21]

Answer:

35/4, or 8 3/4 as a mixed number

Step-by-step explanation:

First, change 58 1/3 into an improper fraction by multiplying the whole number and denominator, then adding the numerator. 58 x 3 equals 174, + 1 equals 175. So, 58 1/3 as an improper fraction is 175/3. Next, change 6 2/3 into an improper fraction. 6 times 3 equals 18, plus 2 equals 20. So, it's 20/3. So, here are your two fractions:

175/3 & 20/3

To divide fractions, I like to use a method called Keep Change Flip. Basically, you keep the first fractions the same, then change the sign. The division sign changes into a multiplication symbol. Now, your equation should look like this: 175/3 x 20/3. Next, flip the fraction from 20/3 into 3/20. This is what your equation should look like now: 175/3 x 3/20. Now you can multiply the fractions together. Before you do so, you can cross reduce to make it easier. What is a number that both 3 and 3 can be divided by? The correct answer is 3. 3/3= 1, so the equation is now 175/1 x 1/20. However, you can continue to cross reduce. You can also divide 175 and 20 by 5, so the equation changes into this: 35/1 x 1/20. Multiply numerator by numerator, denominator by denominator. So, the answer is 35/4, or 8 3/4 as a mixed number. Hope this helped!

5 0
3 years ago
Mr. Jones, 70, is a very active senior. He goes for walks, works in the garden, and occasionally plays tennis. His total daily k
Hatshy [7]

Answer:

The National Academy of Sciences has established the Acceptable Macronutrient Distribution Range (AMDR), which are dietary guidelines regarding the acceptable range of certain nutrients (such as fat, carbohydrates and protein) in our everyday diet. According to the AMDR, 45-65% of our everyday calorie intake should come from carbohydrates. Therefore, 1125 [(2500*45)/100] to 1625 [(2500*65)/100] kilocalories should come from carbohydrates.

Step-by-step explanation:

7 0
3 years ago
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