X - 2y = 3
<span>4x^2 - 5xy + 6y = 3
lets solve for x the first and substitute in the second:
x = 3 + 2y
4(</span>3 + 2y)^2 - 5(3 + 2y)y + 6y = 3
4(9 + 12y + 4y^2) - 15y - 10y^2 = 3
36 + 48y +16y^2<span> - 15y - </span><span>10y^2 = 3
6y^2 + 33y + 33 = 0
we can solve using the general quadratic formula:
y = (-33 +- </span>√(33^2 - 4*6*33)<span>)/12
</span>y = (-33 +- √(297)<span>)/12
</span>so there are 2 solutions for y:
y1 = (-33 + √(297)<span>)/12
</span>y2 = (-33 - √(297)<span>)/12
</span>pick one and then substitute the y value in the first equation to find x
Answer:
The answer is: the second one
Step-by-step explanation:
(2x + 2)/y = 4w + 2
pass y to the right side 2x + 2 = y(4w + 2)
expand 2x +2 = 4wy + 2y
pass 2 to the right 2x = 4wy + 2y -2
pass 2 to the right x = (4wy + 2y - 2)/2
simplify x = 2wy + y - 1 or = 2yw + y -1
2.755778 lbs or round to 2.76 or 3 depending on the question
Answer:
Pattern B gets larger fast since 4 is greater than 3.
explanation:
Pattern A is ; 1, 4, 7, 10, 13
Pattern B: 1, 5, 9, 13, 17
as u can see pattern b goes up faster
