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maxonik [38]
3 years ago
14

Someone plz help me I’m begging you I will give brainliest

Mathematics
1 answer:
azamat3 years ago
8 0

Answer:

\boxed{ \frac{3}{ 4} } \times 7  \: ...    \overline{\underline{\boxed{: }} }\: ... \: 7 \times  \boxed{\frac{3}{4}  } \:...    \overline{\underline{\boxed{: }} }\: ...   \: 3 \times \boxed{ \frac{7}{ 4} } \\  \bull \: they \: all \:  have \: the \: same \: denominator \to \boxed{(4)}\\ \bull \: they \: all \:  have \: the \: same \: numarator \to \boxed{(3 \:  \times 7 \: )}\\ \bull \: they \: all \:  are \: improper \: fractions \: and \: are \: simplified \: to \to \:\boxed{ 5 \frac{1}{4} }

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Two drunks start out together at the origin, each having equal probability of making a step to the left or right along the x axi
pashok25 [27]
They'll meet wen they are sober lol
7 0
3 years ago
110$ for 16ft find the unit rate ​
Neporo4naja [7]

Answer:

6.875 dollars per feet

Step-by-step explanation:

110/16

6.875

8 0
3 years ago
-10ab+2ab^2-9ab+7 what is the simplest form
vesna_86 [32]

Answer:

-19ab + 2ab^2 +7

Step-by-step explanation:

all you do is combine the like terms. and the omly like terms are -10ab and -9ab. 2ab^2 is not one of the like terms simply because of that ^2.

3 0
3 years ago
Find the coordinates of point z such that the ratio of fz to zd is 5;3
Vilka [71]

The point such that the coordinate is 5;3 is (14, 0)

<h3>Midpoint of coordinates using ratio</h3>

The formula for finding the midpoint of a line in the ratio m:n is expressed as:

M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}

Given the coordinate of G and D on the line as G(5, 0) and D(1,0)

Since there is no y-axis, hence;

x = 5(5)+1(3)/2

x = 25+3/2

x = 28/2

x =14

Hence the point such that the ratio is 5;3 is (14, 0)

Learn more on midpoint of a line here: brainly.com/question/5566419

#SPJ1

8 0
2 years ago
Graph the function <br> g(x) = 2(x - 2)^2 + 2
hoa [83]

Answer:

g(x) = 2(x - 2)^2 + 2 plot (see attachment)

Step-by-step explanation:

8 0
4 years ago
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