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3 years ago

What is 3/5 simplified

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

$\dfrac{3}{5}$ is already a simplified fraction.

fiasKO [112]3 years ago

7 0

3/5 simplified is 0.6

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Find the vertical component given that R = 42 lb. and = 80. 41.36 7.29 59.45

valentina_108 [34]

Answer:

Step-by-step explanation:

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2 years ago

Solve 4(x + 3) = 6 Make x the subject

Irina-Kira [14]

Answer:

x = -3/2

Step-by-step explanation:

4(x + 3) = 6

4x + 12 = 6

4x = 6 - 12

4x = -6

x = -6/4

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3 years ago

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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes

Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50% and 50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes per month low user

if x > 400 minutes per month high user

The value for these states are of course yes or no ( the user is low or high user)

Then:

if the user is low today xt (0) we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

Type of user

(xt) xt xt+1

Low (0) or L 0,8 0,2

High(1) or H 0,3 0,7

The resulting equation system is:

xt = 0,8* xt + 0,2* xt+1

xt+1 = 0,3*xt + 0,7* xt+1

1 = xt + xt+1

Solving for variables xt+1 = 1 - xt

xt = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5 and xt+1 = 0,5

b) If in January 0,5 ( 50%) of customesr were low user

In february teh % of low user customer wll be

xt = 0,8* xt + 0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1 xt+1 = 0,5 or 50%

The same answer for March

7 0

3 years ago

Need help on this please and thank you

Ede4ka [16]

Answer:

(1,9)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers