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Anton [14]
2 years ago
7

Help me which one is correct?

Mathematics
2 answers:
kodGreya [7K]2 years ago
6 0

Answer: -m3+m2

Step-by-step explanation: 2m2-[m2(7m-)]6m2

2m2-7m2-m3+6m2

-m3+m2

artcher [175]2 years ago
5 0

Answer:

here is the answer bae. Feel free to ask for more

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hichkok12 [17]
Yeeeeeeeeeer eeee ee e e we. we e e we e e eeeee e e e e e e e e e e e
4 0
3 years ago
Read 2 more answers
Find mZPQR.<br> help asap
DENIUS [597]
<h3>Answer: D) 72</h3>

======================================

Work Shown:

Angle PQR = (far arc - near arc)/2

2x+72 = ( (2x+252) - (2x+108) )/2

2x+72 = 144/2

2x+72 = 72

2x = 72-72

2x = 0

x = 0/2

x = 0

-------------

Angle PQR = 2x+72

Angle PQR = 2(0)+72

Angle PQR = 72 degrees

4 0
2 years ago
2. If mZ1 = 71 degrees, find the measure of the other 7 angles.<br>​
Kobotan [32]
The measure of angles 1,4,5,8 are congruent meaning they’re the exact same. If angle 1 measures 71 degrees then that means that 4,5,8 also measure 71 degrees. Angles 1&2 are supplementary angles which means their sum is 180. Since we know that angle 1 measures 71 then we can find the measure of angle 2 by 71+x=180 and solve for x (angle 2) which is 109
Angles 2,3,6,7 are congruent which means they also equal 109
*** angles 1,4,5,8 = 71
Angles 2,3,6,7 = 109***
3 0
3 years ago
The system of equations is graphed in the figure.
Scilla [17]

Answer:  The correct answer is:  [C]:

___________________________________________

              →    " ( 3, -2) " .

___________________________________________

Explanation:

___________________________________________

By looking at the graph {provided) of the lines of the 2 (two) equations given, we see that the two (2) lines intersect at the point at which the coordinates are:   " (3, -2)" ;  that is:  where:  " x = 3;  y = - 2 " ;  (refer to "image attached");

  →  which corresponds to:

 

  →  Answer choice:  [C]: " (3, -2) " .

___________________________________________

Let us check our answer, by plugging in "3" for "x" ; and "-2" for "y" ;

  in Each of the 2 (two) equations given; to see if the equations hold true:

_____________________________________

Equation 1:

_____________________________________

  y = (-5/3)x  + 3  ;

 →  -2  =? (-5/3)*3  + 3 ?  

 →  -2  =?  -5  + 3 ? ;    -2 =? -2 ?  Yes!

_____________________________________

Equation 2:

_____________________________________

 y = (1/3)x -3 ;

→  -2 =? (1/3)*3  - 3 ? ;

→  -2 =?  1 - 3 ?  ;    -2 = ? -2 ?  Yes!

_____________________________________

Both equations hold true when:  "x = 3 ;  and y = -2 " .

_____________________________________

Refer to image attached to see where the lines of the graphs of the equations given intersect.

_____________________________________

Hope this answer is helpful to you!

  WIshing you the best!

_____________________________________

3 0
2 years ago
What is the sum of the infinite geometric series?<br><br> 120 + 20+ 10/3 + 5/9+...
Sergeu [11.5K]

Answer:

for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

Step-by-step explanation:

i) from the given series we can see that the first term is a_{1 } = 120.

ii) let the common ratio be r.

iii) the second term is 20 = 120 × r

   therefore r = 20 ÷ 120 = \dfrac{1}{6}

iv) the third term is \frac{10}{3} = 20 × r

    therefore r = \dfrac{10}{3} ÷ 20 = \dfrac{1}{6}

v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

6 0
2 years ago
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