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muminat
3 years ago
11

How many factors does 72 have? Eliminat 14

Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

1,2,3,4,6,8,9,12,18,24,36,72,

Step-by-step explanation:

bascally anything that muiply to 72

aalyn [17]3 years ago
6 0

Answer: <u>The factors of 72 are: 1,2,3,4,6,8,9,12,18,24,36,72. So basically 12, and if 72 doesn't count than it is 11.</u>

Step-by-step explanation: <em>Hope this helps.</em>

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3 years ago
Read 2 more answers
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
X^2+y^2-4x+2y=b <br>what is b?
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8 0
3 years ago
If x=4 and y=5. The value of 3x-5y​
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Answer:

13, I believe :)

3 0
3 years ago
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Artyom0805 [142]

Answer:

-3q² + 3qp + 2rp - 2rq + Sq - Sp

Step-by-step explanation:

first part

3q(p-q) = 3qp - 3q²

second part

2r(p-q) = 2rp - 2rq

third part

S(q-p) = Sq - Sp

then we put it all together

3qp - 3q² + 2rp - 2rq + Sq - Sp

in the right place possibly

-3q² + 3qp + 2rp - 2rq + Sq - Sp

8 0
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