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Algebraic 3 more than 5 times a number
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25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path. This can be obtained by considering this as a right angled triangle.
<h3>How fast is the tip of his shadow moving?</h3>Let x be the length between man and the pole, y be the distance between the tip of the shadow and the pole.
Then y - x will be the length between the man and the tip of the shadow.
Since two triangles are similar, we can write
⇒15(y-x) = 6y
15 y - 15 x = 6y
9y = 15x
y = 15/9 x
y = 5/3 x
Differentiate both sides
dy/dt = 5/3 dx/dt
dy/dt is the speed of the tip of the shadow, dx/dt is the speed of the man.
Given that dx/dt = 5 ft/s
Thus dy/dt = (5/3)×5 ft/s
dy/dt = 25/3 ft/s
Hence 25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path.
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Answer:
78 feet
Step-by-step explanation:
<em>COmplete Question is in attached image.</em>
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Eric will want to buy fencing that is sum of perimeter of the square border outside and hexagon inside.
Perimeter is the sum of all sides.
Perimeter of hexagon is sum of 6 sides.
Each side is 5, so
Perimeter of Hexagon = 5 + 5 + 5 + 5 +5 +5 = 30
Now,
Perimeter of Square is sum of all 4 sides measuring 12 each, so
Perimeter of Square = 12 + 12 + 12 + 12 = 48
Total amount of fencing needed = 30 + 48 = 78
