A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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Answer:
The car overtakes the truck at a distance d = 3266.2ft from the starting point
Explanation:
Problem Analysis
When car catches truck:
dc = dt = d
dc: car displacement
dt: truck displacement
tc = tt = t
tc: car time
tt : truck time
car kinematics :
car moves with uniformly accelerated movement:
d = vi*t + (1/2)a*t²
vi = 0 : initial speed
d = (1/2)*a*t² Equation (1)
Truck kinematics:
Truck moves with constant speed:
d = v*t Equation (2)
Data
We know that the acceleration of the car is 3.00 ft / s² and the speed of the truck is 70.0 ft / s .
Development problem
Since the distance traveled by the car is equal to the distance traveled by the truck and the time elapsed is the same for both, then we equate equations (1 ) and (2)
Equation (1) = Equation (2)
(1/2)*a*t² = v*t
(1/2)*3*t² = 70*t (We divide both sides by t)
1.5*t = 70
t = 70 ÷ 1.5
t = 46.66 s
We replace t = 46.66 s in equation (2) to calculate d:
d = 70*46.66 = 3266.2ft
d = 3266.2 ft
Assuming the scooter is moving horizontally on a flat surface, then by Newton's second law, the vertical forces (the normal force and the scooter's weight) cancel out:
<em>n</em> - <em>w</em> = 0
<em>n</em> = <em>w</em>
<em>n</em> = (120 kg) <em>g</em> = 1176 N
(where <em>g</em> = 9.8 m/s²)
Then the friction force has a magnitude of
<em>f</em> = <em>µ</em> <em>n</em>
where <em>µ</em> is the coefficient of kinetic friction, so that
<em>f</em> = 0.4 (1176 N) = 470.4 N ≈ 470 N
The acceleration due to gravity falls off as the inverse of the square of the distance from the center of the Earth. Thus the distance of interest is
1/(d/R)^2 = 0.785/9.8
d = R·√(9.8/0.785) ≈ R·3.53328
or R·2.53328 above the surface of the earth.
Wikipedia says the radius of the earth is 6371 km, so your distance is
(6371 km)·2.53328 ≈ 16,140 km