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dsp73
2 years ago
6

Explain what is happening when the girl is at each point. **The girl has started at 1 and goes to 4.

Physics
1 answer:
Shkiper50 [21]2 years ago
5 0
Gravity
Is happening
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An over-caffeinated student stands on a table which weighs 600 newtons. The student has a mass of 50 kg. What is the weight of t
liberstina [14]

Answer:50kg

Explanation:

6 0
3 years ago
What do you mean by focus in science
Tanzania [10]
“a point at which rays of light, heat, or other radiation meet after being refracted or reflected.” Meaning multiple light rays or heat (and other forms of radiation) are all being refracted or reflecting to a certain point
4 0
2 years ago
A 1200 kg elevator accelerated upwards at 2 m/s2. Draw a force diagram for the elevator. Calculate the force of tension in the c
pishuonlain [190]

Answer:

4800

Explanation:

You have to multiply the 1200 kg and the 2 m/s2. Then multiply the other 2 by the 2400 because it was the answer to the first part now after you multiply your answer is 4800.

6 0
3 years ago
4. A 1,000 kg truck moving at 10 m/s runs into a concrete wall. It takes 0.5 seconds for the truck to conipietery
Maru [420]

Answer:

\large \boxed{\text{h. 20 000 N}}  

Explanation:

Force is the change in momentum over time

F = Δp/Δt

1. Calculate the change in momentum

p₁ = mv₁ = 1000 kg × 10 m/s = 10 000 kg·m·s⁻¹

p₂ = 0

Δp = p₂ - p₁= (0 - 10 000) kg·m·s⁻¹ = -10 000 kg·m·s⁻¹

2. Calculate the force

\begin{array}{rcl}F & = & \dfrac{\Delta p}{\Delta t}\\\\& = & \dfrac{-10 000 \text{ kg$\cdot$m$\cdot$ s}^{-1}}{\text{ 0.5 s}}\\\\& = & \textbf{-20 000 N}\\\end{array}\\\text{The negative sign shows that the force is exerted opposite to the direction of motion.}\\\text{The magnitude of the force is $\large \boxed{\textbf{20 000 N}}$}

3 0
3 years ago
Read 2 more answers
An archer pulls a bowstring back a distance of 20 cm with an average force of 75 N. The arrow has a mass of 20.0 g. When he rele
Masja [62]

To solve this problem we will apply the concepts related to the work theorem for which it is defined as the product of Force and distance. In turn, we will use the energy conservation theorem for which the applied work must be equivalent to the total kinetic energy on the body.

The work is defined as

W = Fd

Here,

F = Force

d = Displacement

Replacing with our values we have that

W = 75*0.2

W = 15J

Now by conservation of energy,

W = KE

W = \frac{1}{2}mv^2

15 = \frac{1}{2} (20*10^{-3}kg)(v^2)

Solving for v,

v = 10\sqrt{15}

v = 38.72 \approx 39

Therefore the correct answer is D.

8 0
3 years ago
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