Explain what is happening when the girl is at each point. **The girl has started at 1 and goes to 4.

Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each

jarptica [38.1K]

Answer with Explanation:

We are given that

$I_1=29 A$

$I_2=78 A$

$d=38 cm=\frac{38}{100}=0.38 m$

$1 m=100 cm$

a.Length of segment,l=20 m

Magnetic force ,F= $\frac{2\mu_0I_1I_2 l}{4\pi d}$

$\frac{\mu_0}{4\pi}=10^{-7}$

Substitute the values

$F=\frac{10^{-7}\times 29\times 78\times 20}{0.38}=0.0119 N$

Hence, the magnetic force exert by each segment on the other=0.0119 N

b.We know that when current carrying in the wires are in same direction then the force will attract to each other.

Hence, the force will be attractive.

4 0

3 years ago

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An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy a

Shtirlitz [24]

Explanation:

${\bold{\sf{\underline{Understanding \: the \: concept}}}}$

✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.

$\bold{↬{ }}$ ${\bold{\sf{\underline{Given \: that}}}}$

✰ Mass = 2 kilograms

✰ Raised height = 10 metres

✰ Posses potential energy = 200 Joules

$\bold{↬{ }}$ ${\bold{\sf{\underline{To \: find}}}}$

✰ Kinetic energy at a height 4 metre

✰ Potential energy at a height 4 metre

${\bold{\sf{\underline{Solution}}}}$

✰ Kinetic energy at a height 4 metre = 120 J

✰ Potential energy at a height 4 metre = 80 J

${\bold{\sf{\underline{Using \: concepts}}}}$

✰ Potential energy formula.

${\bold{\sf{\underline{Using \: formula}}}}$

✰ Potential energy = mgh

${\bold{\sf{\underline{We \: also \: write \: these \: as}}}}$

✰ Potential energy as P.E

✰ Mass as m

✰ Joules as J

✰ Height as h

✰ Raised height as g

${\bold{\sf{\underline{Full \: solution}}}}$

<h3>✠ Let us find the Potential energy.</h3>

↦ Potential energy = mgh

↦ Potential energy = 2 × 10 × 4

↦ Potential energy = 20 × 4

↦ Potential energy = 80 J

<h3>✠ Now according to the question let us find the kinetic energy</h3>

↦ Kinetic energy = Posses potential energy - Finded potential energy

↦ Kinetic energy = 200 J - 80 J

↦ Kinetic energy = 120 Joules

4 0

3 years ago

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A car travels at 12 m/s. The car then accelerates at 3 m/s2 until it reaches a speed of 18m/s.

Galina-37 [17]

Answer:

С. 30 m

Explanation:

Given the following data;

Initial velocity, U = 12m/s

Final velocity, V = 18m/s

Acceleration, a = 3m/s²

To find the distance, we would use the third equation of motion;

V ² = U² + 2aS

Substituting into the equation, we have

18² = 12² + 2*3*S

324 = 144 + 6S

6S = 324 - 144

6S = 180

S = 180/6

Distance, S = 30 meters.

3 0

3 years ago

An object at rest increases its velocity to 10 m/s in 3 seconds. what is its acceleration?

Anna11 [10]

Answer:

30m

Explanation:

10m per second

there is 3 seconds

10 times 3 is 30

4 0

4 years ago

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 98.9 V/m . Calculate the intensity ???? of this

Pani-rosa [81]

Answer:

$intensity = 12.98 W/m^2$

$Energy = 3.93 J$

Explanation:

As we know that the magnitude of electric field intensity is given as

$E = 98.9 V/m$

now we know that intensity of the wave is given as the product of energy density and speed of the wave

$intensity = \frac{1}{2}\epsilon_0 E^2 c$

$intensity = \frac{1}{2}(8.85 \times 10^{-12})(98.9)^2(3\times 10^8)$

$intensity = 12.98 W/m^2$

so intensity is the energy flow per unit area per unit of time

so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as

$Energy = Area \times time \times intensity$

$Energy = 0.0259(11.7)(12.98)$

$Energy = 3.93 J$

7 0

3 years ago