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horrorfan [7]
3 years ago
10

A student wants to determine whether an unknown solid is an ionic compound. He puts some in water and finds that it does not dis

solve. He says that this proves the solid is ionic. Which best evaluates the student's reasoning?
Physics
2 answers:
Bond [772]3 years ago
6 0

Answer:

The student's reasoning is incorrect.  

Many times ionic compounds can be recognized by their properties. Ionic compounds are solids that normally melt at high temperatures and boil at even higher temperatures.

In solid form, an ionic compound is not electrically conductive because its ions cannot flow ("electricity" is the flow of charged particles). However, when it is melted, it can conduct electricity because its ions are able to move freely through the liquid.

Explanation:

Ionic compounds are compounds that have cations and anions.

A polar molecule is one that is neutral, that is, it does not have a net charge. But it has an internal distribution of charges that form a partially positive region and a partially negative region.

Given that "the like dissolves the like" and that water is a polar molecule, it is possible to say that water is good for dissolving ions and polar molecules, but bad for dissolving non-polar molecules.

As mentioned, water molecules are polar, and partial positive charges on hydrogens, a negative partial charge on oxygen and a general angular structure. Its distribution of charges is due to the greater electronegativity of oxygen with respect to hydrogen, which makes the shared electrons of the O-H bonds more attracted by the O atom than by the H atom.

There are water insoluble ionic compounds. For example, silver chloride, AgCl is a very insoluble ionic salt. When mixing a solution of silver nitrate, AgNO3, which contains the Ag + ion, with another solution of sodium chloride containing the Cl– ion, precipitation of AgCl occurs.

But mixing any cation with any anion will not always lead to the formation of an insoluble ionic compound. For example, salt, which is an ionic compound of the NaCl formula, should be considered.

As the salt mixes in the water, the charged water molecules break the charged salt molecules, which are joined by a weaker bond. Then the salt dissociates in water in Na + and Cl-. The positively charged Na + ions are surrounded by the negative partial oxygen charges of the water molecules, while the negatively charged ions are surrounded by the hydrogen ends with a positive partial charge.  Then it can be said that the intermolecular forces that are acting in this case are the ion-dipole forces. This is the force that exists between an ion and a neutral polar molecule that has a permanent dipole moment, where there is electrostatic attraction between a positive ion and the negative end of a solvent molecule and between a negative ion and the positive part of the solvent molecule. In this way the solubility of the ionic compound is produced.

So <u><em>the student's reasoning is incorrect.  </em></u>

<u><em>Many times ionic compounds can be recognized by their properties. Ionic compounds are solids that normally melt at high temperatures and boil at even higher temperatures. </em></u>

<u><em> In solid form, an ionic compound is not electrically conductive because its ions cannot flow ("electricity" is the flow of charged particles). However, when it is melted, it can conduct electricity because its ions are able to move freely through the liquid.</em></u>

Lorico [155]3 years ago
5 0
The student's reasoning is incorrect, because there are many ionic substances that are readily dissolved in water. An example of such a substance is table salt, sodium chloride. Another way of determining the type of bonding is by measuring the melting and boiling point of the solid. Ionic compounds tend to have high melting and boiling points.
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From the given information:

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However, we will have to compute the initial velocity and the acceleration of the duck in their vector forms.

<h3>In vector form;</h3>

The initial velocity is:

\mathbf{u ^{\to} = 0.7 m/s ( -cos 25^0 \hat x + sin 25^0 \hat y ) \ m/s}

The acceleration is:

\mathbf{a ^{\to} = 0.5 m/s ( cos 41^0 \hat x - sin 41^0 \hat y ) \ m/s^2}

The objective of this question is to determine the speed of the duck at a certain time. Since it is not given, let's assume we are to determine the Duck speed after 4 seconds of accelerating;

Then, it implies that time (t) =  4 seconds.

Using the first equation of motion:

v^{\to} = u ^{\to} + a^{\to} t

Then, we can replace their values into the equation of motion in order to determine the speed:

\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+4 \times 0.5 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}

\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+2.0 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}

\mathbf{v^{\to} =\Big( ( -0.7 cos 25^0 \hat x + 0.7 sin 25^0 \hat y )+( 2.0cos 41^0 \hat x - 2.0sin 41^0 \hat y )\Big)}

Collect like terms:

\mathbf{v^{\to} =\Big( (2.0cos 41^0 -0.7 cos 25^0   )\hat x+(  0.7 sin 25^0 - 2.0sin 41^0 )\Big)\hat y}

\mathbf{v^{\to} =0.87500   \hat x- 1.01629 \hat y}

Thus, the magnitude is:

\mathbf{v^{\to} =\sqrt{(0.87500 )^2 +( 1.01629 )^2}}

\mathbf{v^{\to} =\sqrt{0.76563 +1.03285}}

\mathbf{v^{\to} =\sqrt{1.79848}}

\mathbf{v^{\to} =1.34 \ m/s}

Therefore, we can conclude that the speed of the duck after 4 seconds is 1.34 m/s

Learn more about vectors here:

brainly.com/question/17108011?referrer=searchResults

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