We conclude that Jeremy walked 2.37km North and 0.59 km West.
<h3>
How to get the North and West components?</h3>
We can assume that the distance that he walked is the hypotenuse of a right triangle, like the one you can see in the image below.
There, you can see that the adjacent cathetus would be the displacement in the North direction, while the opposite cathetus would be the displacement in the West direction.
Then we can use the relations.
- Sin(θ) = (opposite cathetus)/(hypotenuse)
- Cos(θ) = (adacent cathetus)/(hypotenuse).
With θ = 13.9° and hypotenuse = 2.44km
Solving these two we will get:
sin(13.9°) = Y/2.44km
sin(13.9°)*2.44km = Y = 0.59 km
cos(13.9°) = X/2.44km
cos(13.9°)*2.44km = X = 2.37km
So we can conclude that he walked 2.37km North and 0.59 km West.
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
Answer:
The ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m
Explanation:
Fringe spacing w = λ·D/s
Diffraction grating, d·sin(θ) = n·λ
n = Number of lines
When θ = 90°, we have, sin(θ) = sin(90°) = 1
Therefore;
d·sin(θ) = d × 1 = d = n·λ
When n = 6 lines and d = 550-nm, we have;
d = 6 × 550-nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
Therefore, the ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m.
Answer: 9cm
Explanation:
Refractive index can also be defined as the ratio of the real depth to the apparent depth.
Given that the
Real depth = 12 m
Refractive index of water = 1.33
Refractive index of air = 1.00
nair/nwater = real depth/apparent depth
Substitute all the parameters into the formula
1.33/1 = 12/ apparent depth
Cross multiply
1.33 Apparent depth = 12
Apparent depth = 12/1.33
Apparent depth = 9.02 cm
Therefore, A submerged swimmer in the pool sees the tip of the triangle at 9cm approximately distance above the water.
Answer:
<h2>4.9N approx.</h2>
Explanation:
Step one:
given data
length of rod r= 2.25m
Required torque = 11 Nm
Required
The force needed to produce a torque of 11Nm
Step two:
<em>"By definition, Torque is the twisting force that tends to cause rotation. </em>
<em>The point where the object rotates is known as the axis of rotation."</em>
Mathematically,
= torque
r = radius
F = force
= angle between F and the lever arm
in this case is zero
substituting we have
F=11/2.25
F=4.88N
F=4.9N approx.
Answer:
Magnetic dipole moment is 0.0683 J/T.
Explanation:
It is given that,
Length of the rod, l = 7.3 cm = 0.073 m
Diameter of the cylinder, d = 1.5 cm = 0.015 m
Magnetization, 
The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :
Where
r is the radius of rod, r = 0.0075 m
So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.
