In ΔPQR, the measure of ∠R=90°, the measure of ∠Q=6°, and PQ = 2.2 feet. Find the length of RP to the nearest tenth of a foot.
1 answer:
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Step-by-step explanation:
1. k = 76°
2. r = 25cm
3. as the drawing attached
one pair of parallel lines : AB and DC
one pair of equal angles : <em>L</em><em> </em>A and <em>L</em><em> </em>D
4. (7²× 3`¹)⁴×7^5 / (3² × 7^(-6))³
= (7^8 × 3`⁴)×7^5/ (3² × 7^(-6))³
= (7^13 × 3`⁴)/ (3^6 × 7^(-18))
= (7^(31) × 3^(-10))
= 7^31 / 3^10
