<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3-a%7D%7B6%7D%20-%5Cfrac%7B6-a%7D%7B3%7D%20%3Da%2B1%3Cbr%3E%0A%20" id="TexFormula

All categories

3 years ago

1" title=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " alt=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " align="absmiddle" class="latex-formula">
Find a

Mathematics

1 answer:

Reika [66]3 years ago

8 0

$\frac{3-a}{6} -\frac{6-a}{3} =a+1; 
\\ \\ \frac{3-a}{6} -\frac{2(6-a)}{3*2} =a+1
\\ \\ \frac{3-a-12+2a}{6} =a+1
\\ \\ 6*\frac{a-9}{6} = 6*(a+1)
\\ \\ a-9 = 6a+6
\\ \\ 5a= -15
\\ \\ a=-3$

You might be interested in

Please help! Create a set of five positive numbers (repeats allowed) that have a median of 10 and a mean of 14. What thought pro

Brilliant_brown [7]

Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53

6 0

3 years ago

Which three lengths could be the lengths

Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

$4+8=12$

$4+8$

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

$13+11=24$

$13+11>23$

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

$5+12=17$

$5+12$

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

$8+16=24$

$8+16$

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0

3 years ago

Myles said that 5 x 0.13 is 6.5. Do you agree? Explain. Brainliest if correct!

77julia77 [94]

No he is not, 10*0.13=1.3, so 5*0.13=0.65

6 0

3 years ago

Read 2 more answers

Find the value of x. 1) 46° x

ehidna [41]

There's no question there. You didn't attach the pic

6 0

3 years ago

A fruit vendor sells 85 pieces of fruit that are either apples or oranges. The ratio of apples to oranges is 3:2. How many apple

crimeas [40]

53. The ratio of apple over orange = 3:2 The total number of fruits are 60 pieces. Now, find the total number of apples and total number of oranges. => first, let’s add 2 + 3 = 5 Thus, we have 5 division for 60 pieces fruits, => 60 / 5 => 12 let’s solve for the apple => 12 x 3 = 36 Now. The orange => 12 * 2 = 24 => 36 + 24 = 60 Thus the ratio is 36 : 24

5 0

3 years ago