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3 years ago

1" title=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " alt=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " align="absmiddle" class="latex-formula">
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Mathematics

1 answer:

Reika [66]3 years ago

8 0

$\frac{3-a}{6} -\frac{6-a}{3} =a+1; 
\\ \\ \frac{3-a}{6} -\frac{2(6-a)}{3*2} =a+1
\\ \\ \frac{3-a-12+2a}{6} =a+1
\\ \\ 6*\frac{a-9}{6} = 6*(a+1)
\\ \\ a-9 = 6a+6
\\ \\ 5a= -15
\\ \\ a=-3$

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