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dusya [7]
3 years ago
15

1" title=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " alt=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " align="absmiddle" class="latex-formula">
Find a
Mathematics
1 answer:
Reika [66]3 years ago
8 0
\frac{3-a}{6} -\frac{6-a}{3} =a+1; 
\\ \\  \frac{3-a}{6} -\frac{2(6-a)}{3*2} =a+1
\\ \\  \frac{3-a-12+2a}{6} =a+1
\\ \\ 6*\frac{a-9}{6} = 6*(a+1)
\\ \\ a-9 = 6a+6
\\ \\ 5a= -15
\\ \\ a=-3
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Plz, Help me with this question.
UNO [17]

Answer:

first option

Step-by-step explanation:

Given

area = 15x - 9 ← factor out 3 from each term

       = 3(5x - 3)

Thus the dimensions are 3 by (5x - 3)

6 0
3 years ago
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H(n)=n^2-1; find h(4)
LiRa [457]

Answer:

h(4)=4²-1

=16-1

=15

hope it helps.

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3 years ago
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In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:
Alexxx [7]

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

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HE × DC = EB × HD

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Step-by-step explanation:

3 0
3 years ago
All ratios equivalent to 8:10.
dangina [55]
First you have to figure out the GCF (Greatest Common Factor) of 8 and 10. When you figure that out, the GCF is 2. So then, you would divide 2 by 8 and 10, then you should get the answer which is 4/5.
5 0
3 years ago
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Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =
Vitek1552 [10]
So here is how we are going to find out what is ED. 
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5. 
Hope this answer helps. Let me know if you need more help next time!</span>
5 0
4 years ago
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