Question

1" title=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " alt=" \frac{3-a}{6} -\frac{6-a}{3} =a+1
 " align="absmiddle" class="latex-formula">
Find a

Answer 1

$\frac{3-a}{6} -\frac{6-a}{3} =a+1; \\ \\ \frac{3-a}{6} -\frac{2(6-a)}{3*2} =a+1 \\ \\ \frac{3-a-12+2a}{6} =a+1 \\ \\ 6*\frac{a-9}{6} = 6*(a+1) \\ \\ a-9 = 6a+6 \\ \\ 5a= -15 \\ \\ a=-3$