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Arturiano [62]
2 years ago
10

Graph the given inequality. -3 > n How do I do this?

Mathematics
1 answer:
Lelu [443]2 years ago
3 0

-3 > n is the same as n < -3 after you flip both sides and flip the inequality.

To graph this, we place an open hole at -3 on the number line. Then we shade to the left to indicate all values smaller than -3. The open hole says "the endpoint is not included". This is because -3 is not smaller than itself.

We would have a filled in circle if we had "or equal to" as part of the inequality, but we don't.

The graph is shown below.

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Determine the equation of the line passing through the points (3,1) and (5,−1).
katrin [286]

Answer:

y=-x+4

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m=(y2-y1)/(x2-x1)

m=(-1-1)/(5-3)

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5 0
2 years ago
For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r &lt; d. n = −67, d = 8
Firlakuza [10]

Answer:

q = 8

r = 3

Step-by-step explanation:

Given

n = dq + r

0 \le r < d

n = 67 --- not -67

d = 8

Required

Find q and r

Substitute values for d and b

n = dq + r

67 = 8 * q + r

67 = 8q + r

Make q the subject

q = \frac{67 - r}{8}

0 \le r < d means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let r = 3

q = \frac{67 - 3}{8}

q = \frac{64}{8}

q = 8

No other true values of r and q can be gotten.

7 0
3 years ago
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